What is the limit as x approaches-9 of 1/((x+9)^2) ?

The limit as x approaches-9 of 1/((x+9)^2) is infinity

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limit as x approaches-9 of 1/((x+9)^2)

x \to - 9 lim (\frac{1}{( x + 9 ) ^{2}})

\infty

Solution steps

x \to - 9 lim (\frac{1}{( x + 9 ) ^{2}})

x \to a - lim f (x) = x \to a + lim f (x) = L

then

x \to a lim f (x) = L

x \to - 9 - lim (\frac{1}{( x + 9 ) ^{2}}) = \infty

x \to - 9 + lim (\frac{1}{( x + 9 ) ^{2}}) = \infty

= \infty

\int cos^{3} (3 x) sin^{- 2} (3 x) d x

x \to - \infty lim (19)

x \to 5 lim (9)

f (x) = x - x^{2}, at x = - 1

f (x) = 3 x^{5}

What is the limit as x approaches-9 of 1/((x+9)^2) ?
The limit as x approaches-9 of 1/((x+9)^2) is infinity