What is area x=5y^2,x=1+4y^2 ?

The answer to area x=5y^2,x=1+4y^2 is No Solution

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area x=5y^2,x=1+4y^2

area

x = 5 y^{2}, x = 1 + 4 y^{2}

No Solution

Solution steps

Isolate

y

for

x = 5 y^{2} : y = \frac{x}{5}, y = - \frac{x}{5}

Isolate

y

for

x = 1 + 4 y^{2} : y = \frac{x - 1}{2}, y = - \frac{x - 1}{2}

f_{1} (x) = \frac{x}{5}

f_{2} (x) = - \frac{x}{5}

To find the intersection points solve

f_{i} (x) = f_{j} (x)

\frac{x}{5} = - \frac{x}{5} : x = 0

\frac{x}{5} = \frac{x - 1}{2} : x = 5

\frac{x}{5} = - \frac{x - 1}{2} :

No Solution for

x \in R

- \frac{x}{5} = \frac{x - 1}{2} :

No Solution for

x \in R

- \frac{x}{5} = - \frac{x - 1}{2} : x = 5

\frac{x - 1}{2} = - \frac{x - 1}{2} : x = 1

Curves not bounded

= No Solution

3 x^{- \frac{3}{2}} + 6 x^{- \frac{1}{2}} + x^{3} - 4

y = e^{3 x}

\frac{d}{d x} ((x^{2} + 1) e^{x})

2 3 x

\int x 16 - x^{2} d x

What is area x=5y^2,x=1+4y^2 ?
The answer to area x=5y^2,x=1+4y^2 is No Solution