What is (\partial}{\partial x}(\frac{x^2)/4) ?

The answer to (\partial}{\partial x}(\frac{x^2)/4) is x/2

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(\partial}{\partial x}(\frac{x^2)/4)

\frac{\partial}{\partial x} (\frac{x ^{2}}{4})

\frac{x}{2}

Solution steps

\frac{\partial}{\partial x} (\frac{x ^{2}}{4})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{4} \frac{\partial}{\partial x} (x^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{1}{4} \cdot 2 x^{2 - 1}

Simplify

\frac{1}{4} \cdot 2 x^{2 - 1} : \frac{x}{2}

= \frac{x}{2}

\frac{\partial}{\partial x} (x^{6} y^{4} - x^{5} y^{3})

\int (\frac{1}{x ^{2} - 4}) d x

(0, - 3), (- 4, 2)

s^{3}

\int + \frac{sin ( x )}{cos ( x ) - cos ^{2} ( x )} d x

What is (\partial}{\partial x}(\frac{x^2)/4) ?
The answer to (\partial}{\partial x}(\frac{x^2)/4) is x/2