What is the derivative of-sin(3x3) ?

The derivative of-sin(3x3) is -9cos(3x)

What is the first derivative of-sin(3x3) ?

The first derivative of-sin(3x3) is -9cos(3x)

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\frac{d}{d x} (- sin (3 x) 3)

- 9 cos (3 x)

Solution steps

\frac{d}{d x} (- sin (3 x) \cdot 3)

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 3 \frac{d}{d x} (sin (3 x))

Apply the chain rule:

cos (3 x) \frac{d}{d x} (3 x)

= cos (3 x) \frac{d}{d x} (3 x)

\frac{d}{d x} (3 x) = 3

= - 3 cos (3 x) \cdot 3

Simplify

= - 9 cos (3 x)

\int (2 x + 1)^{- 1} d x

x \to + 0 lim (\frac{2 sin ( 2 x )}{x})

\int \frac{x ^{2}}{x ^{3} + 4} d x

10 y^{^{''}} - 7 y^{^{'}} - 12 y = 0

x \to 2 - lim (x + 3)

What is the derivative of-sin(3x3) ?
The derivative of-sin(3x3) is -9cos(3x)
What is the first derivative of-sin(3x3) ?
The first derivative of-sin(3x3) is -9cos(3x)