What is the derivative of 7xe^xcos(x) ?

The derivative of 7xe^xcos(x) is 7(e^xcos(x)+x(e^xcos(x)-e^xsin(x)))

What is the first derivative of 7xe^xcos(x) ?

The first derivative of 7xe^xcos(x) is 7(e^xcos(x)+x(e^xcos(x)-e^xsin(x)))

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derivative of

7 x e^{x} cos (x)

7 (e^{x} cos (x) + x (e^{x} cos (x) - e^{x} sin (x)))

Solution steps

\frac{d}{d x} (7 x e^{x} cos (x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 7 \frac{d}{d x} (x e^{x} cos (x))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x, g = e^{x} cos (x)

= 7 (\frac{d x}{d x} e^{x} cos (x) + \frac{d}{d x} (e^{x} cos (x)) x)

\frac{d x}{d x} = 1

\frac{d}{d x} (e^{x} cos (x)) = e^{x} cos (x) - e^{x} sin (x)

= 7 (1 \cdot e^{x} cos (x) + (e^{x} cos (x) - e^{x} sin (x)) x)

Simplify

= 7 (e^{x} cos (x) + x (e^{x} cos (x) - e^{x} sin (x)))

\int ln (x) + x d x

\int sin^{3} (18 x) d x

\int sec^{4 x} (d) x d x

\frac{d}{d x} (\frac{x ^{2} - 64}{x + 8})

g (t) = (9 t + 5)^{2} (5 t - 6)^{- 3}

What is the derivative of 7xe^xcos(x) ?
The derivative of 7xe^xcos(x) is 7(e^xcos(x)+x(e^xcos(x)-e^xsin(x)))
What is the first derivative of 7xe^xcos(x) ?
The first derivative of 7xe^xcos(x) is 7(e^xcos(x)+x(e^xcos(x)-e^xsin(x)))