What is the solution for (x^2+1)(dy)/(dx)+3x(y-1)=0 ?

The solution for (x^2+1)(dy)/(dx)+3x(y-1)=0 is y=(c_{1})/((x^2+1)^{3/2)}+1

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(x^2+1)(dy)/(dx)+3x(y-1)=0

(x^{2} + 1) \frac{d y}{d x} + 3 x (y - 1) = 0

y = \frac{c _{1}}{( x ^{2} + 1 ) ^{\frac{3}{2}}} + 1

Solution steps

(x^{2} + 1) \frac{d y}{d x} + 3 x (y - 1) = 0

Solve separable ODE:

y = \frac{c _{1}}{( x ^{2} + 1 ) ^{\frac{3}{2}}} + 1

y = \frac{c _{1}}{( x ^{2} + 1 ) ^{\frac{3}{2}}} + 1

\frac{d}{d x} (\frac{x}{tan ( x )})

\frac{2 e ^{- 2 s}}{s ( s + 2 ) ( s + 3 ) ^{2}}

x \to a lim (2 f (x) - 3 g (x))

\frac{d}{d x} ((x^{2} + a^{2})^{e^{x^{2}}})

\frac{d}{d y} (\frac{- y}{x ^{2} + y ^{2}})

What is the solution for (x^2+1)(dy)/(dx)+3x(y-1)=0 ?
The solution for (x^2+1)(dy)/(dx)+3x(y-1)=0 is y=(c_{1})/((x^2+1)^{3/2)}+1