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Popular >

xy^'+y=x

Solution

x y^{^{'}} + y = x

Solution

y = \frac{x}{2} + \frac{c _{1}}{x}

Solution steps

x y^{'} (x) + y = x

Solve linear ODE:

y = \frac{x}{2} + \frac{c _{1}}{x}

y = \frac{x}{2} + \frac{c _{1}}{x}

Popular Examples

derivative of ((-5x+1^3)/((3x-3)^6))

\frac{d}{d x} (\frac{( - 5 x + 1 ) ^{3}}{( 3 x - 3 ) ^{6}})

(\partial)/(\partial x)(x^2-y^2-2z^2)

\frac{\partial}{\partial x} (x^{2} - y^{2} - 2 z^{2})

derivative of (12x^5+8x^3-2x^2/(4x^2))

\frac{d}{d x} (\frac{12 x ^{5} + 8 x ^{3} - 2 x ^{2}}{4 x ^{2}})

derivative of 8/(e^x+e^{-x)}derivative of

\frac{8}{e ^{x} + e ^{- x}}

taylor e^{-6x},0 taylor

e^{- 6 x}, 0

Frequently Asked Questions (FAQ)

What is the solution for xy^'+y=x ?
The solution for xy^'+y=x is y= x/2+(c_{1})/x