What is the solution for (d^2y)/(dx^2)+2(dy)/(dx)+2y=0 ?

The solution for (d^2y)/(dx^2)+2(dy)/(dx)+2y=0 is y=e^{-x}(c_{1}cos(x)+c_{2}sin(x))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(d^2y)/(dx^2)+2(dy)/(dx)+2y=0

\frac{d ^{2} y}{d x ^{2}} + 2 \frac{d y}{d x} + 2 y = 0

y = e^{- x} (c_{1} cos (x) + c_{2} sin (x))

Solution steps

\frac{d ^{2} y}{d x ^{2}} + 2 \frac{d y}{d x} + 2 y = 0

Solve linear ODE:

y = e^{- x} (c_{1} cos (x) + c_{2} sin (x))

y = e^{- x} (c_{1} cos (x) + c_{2} sin (x))

10 y^{^{''}} + 1000 y = 140 cos (8 t)

\int e^{2 x + 3} d x

\frac{d}{d x} (x^{2} - 2 x - 2 sin (x - 2))

\int \frac{sin ( 6 e ^{- 2 x} )}{e ^{2 x}} d x

What is the solution for (d^2y)/(dx^2)+2(dy)/(dx)+2y=0 ?
The solution for (d^2y)/(dx^2)+2(dy)/(dx)+2y=0 is y=e^{-x}(c_{1}cos(x)+c_{2}sin(x))