What is the derivative of sqrt(x+1) ?

The derivative of sqrt(x+1) is 1/(2sqrt(x+1))

What is the first derivative of sqrt(x+1) ?

The first derivative of sqrt(x+1) is 1/(2sqrt(x+1))

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derivative of

x + 1

\frac{1}{2 x + 1}

Solution steps

\frac{d}{d x} (x + 1)

Apply the chain rule:

\frac{1}{2 x + 1} \frac{d}{d x} (x + 1)

= \frac{1}{2 x + 1} \frac{d}{d x} (x + 1)

\frac{d}{d x} (x + 1) = 1

= \frac{1}{2 x + 1} \cdot 1

Simplify

= \frac{1}{2 x + 1}

\frac{4 s + 7}{s ^{2} - 4}

\int \frac{x ^{2}}{x ^{2} + 1} d x

(y + 1) (\frac{d y}{d x}) = 2 x

y^{^{''}} - 7 y^{^{'}} + 12 y = 0, y (0) = - \frac{1}{2}, y^{^{'}} (0) = - \frac{9}{4}

\int \frac{15 e ^{5 y}}{e ^{5 y} + 2} d y

What is the derivative of sqrt(x+1) ?
The derivative of sqrt(x+1) is 1/(2sqrt(x+1))
What is the first derivative of sqrt(x+1) ?
The first derivative of sqrt(x+1) is 1/(2sqrt(x+1))