What is the tangent of 2x^2-7x+5 ?

The tangent of 2x^2-7x+5 is y=(4a_{0}-7)x-2a_{0}^2+5

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tangent of 2x^2-7x+5

tangent of

2 x^{2} - 7 x + 5

y = (4 a_{0} - 7) x - 2 a_{0}^{2} + 5

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, 2 a_{0}^{2} - 7 a_{0} + 5)

Find the slope of

y = 2 x^{2} - 7 x + 5 : \frac{d y}{d x} = 4 x - 7

Compute the slope of

y = 2 x^{2} - 7 x + 5

x = a_{0} : m = 4 a_{0} - 7

Find the line with slope m=

4 a_{0} - 7

and passing through

(a_{0}, 2 a_{0}^{2} - 7 a_{0} + 5) : y = (4 a_{0} - 7) x - 2 a_{0}^{2} + 5

y = (4 a_{0} - 7) x - 2 a_{0}^{2} + 5

(x + \frac{4}{x})^{^{'}}

\frac{\partial}{\partial x} (e^{- (x^{2} + y^{2} + z^{2})})

\int (x + 2)^{5} d x

\int \frac{1}{3} e^{- \frac{x}{3}} d x

x \to - 4 - lim (x^{2} + \frac{2}{x + 4})

What is the tangent of 2x^2-7x+5 ?
The tangent of 2x^2-7x+5 is y=(4a_{0}-7)x-2a_{0}^2+5