What is the derivative of 2/x-3x ?

The derivative of 2/x-3x is -2/(x^2)-3

What is the first derivative of 2/x-3x ?

The first derivative of 2/x-3x is -2/(x^2)-3

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\frac{d}{d x} (\frac{2}{x} - 3 x)

- \frac{2}{x ^{2}} - 3

Solution steps

\frac{d}{d x} (\frac{2}{x} - 3 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{2}{x}) - \frac{d}{d x} (3 x)

\frac{d}{d x} (\frac{2}{x}) = - \frac{2}{x ^{2}}

\frac{d}{d x} (3 x) = 3

= - \frac{2}{x ^{2}} - 3

θ \to - π + lim (csc (θ))

\int - \frac{1}{4} cos (4 x) d x

\int \frac{1 + x}{x x} d x

\frac{d y}{d x} + 2 y = 0

\frac{d}{d x} (\frac{2 x sin ( x )}{3 + cos ( x )})

What is the derivative of 2/x-3x ?
The derivative of 2/x-3x is -2/(x^2)-3
What is the first derivative of 2/x-3x ?
The first derivative of 2/x-3x is -2/(x^2)-3