What is the tangent of f(x)=2xsqrt(1-3x),\at x=-2 ?

The tangent of f(x)=2xsqrt(1-3x),\at x=-2 is y=(20)/(sqrt(7))x-4sqrt(7)+(40)/(sqrt(7))

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tangent of f(x)=2xsqrt(1-3x),\at x=-2

tangent of

f (x) = 2 x 1 - 3 x, at x = - 2

y = \frac{20}{7} x - 47 + \frac{40}{7}

Solution steps

Find the tangent point:

(- 2, - 47)

Find the slope of

f (x) = 2 x 1 - 3 x : \frac{df ( x )}{d x} = \frac{- 9 x + 2}{1 - 3 x}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = \frac{20}{7}

Find the line with slope m=

\frac{20}{7}

and passing through

(- 2, - 47) : y = \frac{20}{7} x - 47 + \frac{40}{7}

y = \frac{20}{7} x - 47 + \frac{40}{7}

\int \frac{1}{x ^{2} - 3 x - 4} d x

\int (x + 1)^{\frac{3}{2}} d x

\frac{d}{d x} (e^{t a n^{2} (x)})

\frac{\partial}{\partial x} (x + 9 y + 8 z)

\frac{d}{d x} (\frac{7}{3 x ^{7} - 12 x ^{6} + 2 x ^{2} - 9})

What is the tangent of f(x)=2xsqrt(1-3x),\at x=-2 ?
The tangent of f(x)=2xsqrt(1-3x),\at x=-2 is y=(20)/(sqrt(7))x-4sqrt(7)+(40)/(sqrt(7))