What is (\partial)/(\partial x)(x^2y+x+y) ?

The answer to (\partial)/(\partial x)(x^2y+x+y) is 2xy+1

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(\partial)/(\partial x)(x^2y+x+y)

\frac{\partial}{\partial x} (x^{2} y + x + y)

2 x y + 1

Solution steps

\frac{\partial}{\partial x} (x^{2} y + x + y)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x^{2} y) + \frac{\partial}{\partial x} (x) + \frac{\partial}{\partial x} (y)

\frac{\partial}{\partial x} (x^{2} y) = 2 y x

\frac{\partial}{\partial x} (x) = 1

\frac{\partial}{\partial x} (y) = 0

= 2 y x + 1 + 0

Simplify

= 2 x y + 1

((x - 1)^{2})^{^{'}}

\frac{\partial}{\partial z} (7 z e^{x yz})

\frac{1}{( x ^{2} - 3 ) ( x ^{2} + 3 x + 5 )}

\frac{\partial}{\partial y} (y (y + sin (x)))

\int_{0}^{0.6} \frac{x ^{2}}{9 - 25 x ^{2}} d x

What is (\partial)/(\partial x)(x^2y+x+y) ?
The answer to (\partial)/(\partial x)(x^2y+x+y) is 2xy+1