What is the derivative of x^5*ln(x) ?

The derivative of x^5*ln(x) is 5x^4ln(x)+x^4

What is the first derivative of x^5*ln(x) ?

The first derivative of x^5*ln(x) is 5x^4ln(x)+x^4

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\frac{d}{d x} (x^{5} \cdot ln (x))

5 x^{4} ln (x) + x^{4}

Solution steps

\frac{d}{d x} (x^{5} ln (x))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x^{5}, g = ln (x)

= \frac{d}{d x} (x^{5}) ln (x) + \frac{d}{d x} (ln (x)) x^{5}

\frac{d}{d x} (x^{5}) = 5 x^{4}

\frac{d}{d x} (ln (x)) = \frac{1}{x}

= 5 x^{4} ln (x) + \frac{1}{x} x^{5}

\frac{1}{x} x^{5} = x^{4}

= 5 x^{4} ln (x) + x^{4}

\frac{d}{d x} (x^{2} - a^{2})

n = 0 \sum \infty \frac{1}{3 ^{n - 1}}

y = \frac{1}{ln ( x )}

x \to 5 lim (\frac{x}{∣ x - 5 ∣})

y = x^{2} - x, (1, 0)

What is the derivative of x^5*ln(x) ?
The derivative of x^5*ln(x) is 5x^4ln(x)+x^4
What is the first derivative of x^5*ln(x) ?
The first derivative of x^5*ln(x) is 5x^4ln(x)+x^4