What is (\partial)/(\partial x)(9ye^x-ln(z)) ?

The answer to (\partial)/(\partial x)(9ye^x-ln(z)) is 9e^xy

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(\partial)/(\partial x)(9ye^x-ln(z))

\frac{\partial}{\partial x} (9 y e^{x} - ln (z))

9 e^{x} y

Solution steps

\frac{\partial}{\partial x} (9 y e^{x} - ln (z))

Treat

y, z

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (9 y e^{x}) - \frac{\partial}{\partial x} (ln (z))

\frac{\partial}{\partial x} (9 y e^{x}) = 9 y e^{x}

\frac{\partial}{\partial x} (ln (z)) = 0

= 9 y e^{x} - 0

Simplify

= 9 e^{x} y

\frac{s + 2}{s ^{2} + 2 s + 5}

(t - 2) e^{- 4 t}

4 x + \frac{144}{x} + 80

\frac{d}{d x} (lo g_{e} (x^{2} + x + 1))

\frac{d}{d x} ((- 3 x^{5} - 3)^{3})

What is (\partial)/(\partial x)(9ye^x-ln(z)) ?
The answer to (\partial)/(\partial x)(9ye^x-ln(z)) is 9e^xy