What is the integral from 0 to 20 of 3x ?

The integral from 0 to 20 of 3x is 600

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integral from 0 to 20 of 3x

\int_{0}^{20} 3 x d x

600

Solution steps

\int_{0}^{20} 3 x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int_{0}^{20} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{0}^{20}

= 3 [\frac{x ^{2}}{2}]_{0}^{20}

Compute the boundaries:

200

= 3 \cdot 200

Simplify

= 600

\int \frac{1}{t ^{2} 100 - t ^{2}} d t

x \to 0 lim (ln (cos (x)))

4 t y^{^{'}} + 4 = 5 + t

x \to 0 lim (0^{0})

f (x) = \frac{x ^{2}}{x + 3}

What is the integral from 0 to 20 of 3x ?
The integral from 0 to 20 of 3x is 600