What is the integral of tan(5x) ?

The integral of tan(5x) is -1/5 ln|cos(5x)|+C

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integral of tan(5x)

\int tan (5 x) d x

- \frac{1}{5} ln ∣ cos (5 x) ∣ + C

Solution steps

\int tan (5 x) d x

Rewrite using trig identities

= \int \frac{sin ( 5 x )}{cos ( 5 x )} d x

Apply u-substitution

: \int - \frac{1}{5 u} d u

= \int - \frac{1}{5 u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \frac{1}{5} \cdot \int \frac{1}{u} d u

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= - \frac{1}{5} ln ∣ u ∣

Substitute back

u = cos (5 x)

= - \frac{1}{5} ln ∣ cos (5 x) ∣

Add a constant to the solution

= - \frac{1}{5} ln ∣ cos (5 x) ∣ + C

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\int (- \frac{3}{10 - 10 x ^{2}}) d x

y = 3 tan (2 x)

\int \frac{- 6}{x ^{2} x ^{2} - 9} d x

\frac{d}{d x} (\frac{1}{( 1 + x ^{2} ) ^{\frac{1}{2}}})