What is area y=18sin(x),y=18cos(x) ?

The answer to area y=18sin(x),y=18cos(x) is 36sqrt(2)

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area y=18sin(x),y=18cos(x)

area

y = 18 sin (x), y = 18 cos (x)

362

Decimal

50.91168 \dots

Solution steps

Apply the area formula:

\int_{\frac{π}{4}}^{\frac{5 π}{4}} ∣ 18 sin (x) - 18 cos (x) ∣ d x

Solve

\int_{\frac{π}{4}}^{\frac{5 π}{4}} ∣ 18 sin (x) - 18 cos (x) ∣ d x : 362

The area is:

= 362

x^{2} - 4 x + 3, - x^{2} + 2 x + 3, 4, 0

t^{2} \frac{d y}{d t} - t = 1 + y + t y, y (1) = 8

y = \frac{ln ( 6 x )}{6 x}

\frac{d ^{2}}{d x ^{2}} (11 x)

n = 1 \sum \infty \frac{6}{n ( n + 2 )}

What is area y=18sin(x),y=18cos(x) ?
The answer to area y=18sin(x),y=18cos(x) is 36sqrt(2)