What is (\partial)/(\partial x)(4x^5-2y^{-3}) ?

The answer to (\partial)/(\partial x)(4x^5-2y^{-3}) is 20x^4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)(4x^5-2y^{-3})

\frac{\partial}{\partial x} (4 x^{5} - 2 y^{- 3})

20 x^{4}

Solution steps

\frac{\partial}{\partial x} (4 x^{5} - 2 y^{- 3})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (4 x^{5}) - \frac{\partial}{\partial x} (2 y^{- 3})

\frac{\partial}{\partial x} (4 x^{5}) = 20 x^{4}

\frac{\partial}{\partial x} (2 y^{- 3}) = 0

= 20 x^{4} - 0

Simplify

= 20 x^{4}

\frac{9 + 2 x - 6 x}{x}

y^{^{''}} + y^{^{'}} - 2 y = 0

\frac{d}{d x} (- x^{4} + 50 x^{2} - 300)

(4.1) (7.1)

\int_{2}^{\infty} x e^{- 5 x} d x

What is (\partial)/(\partial x)(4x^5-2y^{-3}) ?
The answer to (\partial)/(\partial x)(4x^5-2y^{-3}) is 20x^4