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Popular >

y^'+(2/x)y=0

Solution

y^{^{'}} + (\frac{2}{x}) y = 0

Solution

y = \frac{c _{1}}{x ^{2}}

Solution steps

y^{'} (x) + (\frac{2}{x}) y = 0

Solve separable ODE:

y = \frac{c _{1}}{x ^{2}}

y = \frac{c _{1}}{x ^{2}}

Graph

Popular Examples

integral of ((1-x)/x)^2

\int (\frac{1 - x}{x})^{2} d x

tangent of f(x)=5+5x^2-2x^3,\at x=2 tangent of

f (x) = 5 + 5 x^{2} - 2 x^{3}, at x = 2

(\partial)/(\partial x)((G(m,x)m)/(x^2))

\frac{\partial}{\partial x} (\frac{G ( m , x ) m}{x ^{2}})

integral of (-3e^{sqrt(5x)})/(sqrt(5x))

\int \frac{- 3 e ^{5 x}}{5 x} d x

simplify e^{ln(cos(x^2))}sqrt(2x+1)simplify

e^{l n (c o s (x^{2}))} 2 x + 1

Frequently Asked Questions (FAQ)

What is the solution for y^'+(2/x)y=0 ?
The solution for y^'+(2/x)y=0 is y=(c_{1})/(x^2)