What is laplacetransform f(t)=1*t^3 ?

The answer to laplacetransform f(t)=1*t^3 is 6/(s^4)

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laplacetransform f(t)=1*t^3

laplace transform

f (t) = 1 \cdot t^{3}

\frac{6}{s ^{4}}

Solution steps

L {1 \cdot t^{3}}

Use the constant multiplication property of Laplace Transform:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= 1 L {t^{3}}

L {t^{3}} : \frac{6}{s ^{4}}

= 1 \cdot \frac{6}{s ^{4}}

Refine

1 \frac{6}{s ^{4}} : \frac{6}{s ^{4}}

= \frac{6}{s ^{4}}

\frac{d}{d x} (x + lo g_{e} (x))

x^{2} - x

\frac{d x}{d t} - 4 x = cos (5 t)

f (x) = - 3 x^{3} - 2 x^{2} - x + 3, (-, 5)

n = 1 \sum \infty \frac{1}{n ^{7}}

What is laplacetransform f(t)=1*t^3 ?
The answer to laplacetransform f(t)=1*t^3 is 6/(s^4)