What is the derivative of tan^9(x) ?

The derivative of tan^9(x) is 9tan^8(x)sec^2(x)

What is the first derivative of tan^9(x) ?

The first derivative of tan^9(x) is 9tan^8(x)sec^2(x)

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derivative of

tan^{9} (x)

9 tan^{8} (x) sec^{2} (x)

Solution steps

\frac{d}{d x} (tan^{9} (x))

Apply the chain rule:

9 (tan (x))^{8} \frac{d}{d x} (tan (x))

= 9 (tan (x))^{8} \frac{d}{d x} (tan (x))

\frac{d}{d x} (tan (x)) = sec^{2} (x)

= 9 (tan (x))^{8} sec^{2} (x)

Simplify

= 9 tan^{8} (x) sec^{2} (x)

x \to 2 - lim (\frac{x + 1}{4 - x ^{2}})

\int 3 - t^{2} d t

f (t) = \frac{2 t + 1}{t + 3}

\int \frac{x ^{2}}{1 - x ^{3}} d x

\int \frac{2}{x ^{2} + 16} d x

What is the derivative of tan^9(x) ?
The derivative of tan^9(x) is 9tan^8(x)sec^2(x)
What is the first derivative of tan^9(x) ?
The first derivative of tan^9(x) is 9tan^8(x)sec^2(x)