What is the integral of 10abcx^2 ?

The integral of 10abcx^2 is (10abcx^3)/3+C

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integral of 10abcx^2

\int 10 ab c x^{2} d x

\frac{10 ab c x ^{3}}{3} + C

Solution steps

\int 10 ab c x^{2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 10 ab c \cdot \int x^{2} d x

Apply the Power Rule

: \frac{x ^{3}}{3}

= 10 ab c \frac{x ^{3}}{3}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{10 ab c x ^{3}}{3}

Add a constant to the solution

= \frac{10 ab c x ^{3}}{3} + C

\frac{d}{d x} (- \frac{20}{x ^{3}})

cos (cos (x))

\int 4 - x^{2} d x

\int \frac{45}{x + 1} d x

(\frac{y}{x} + 9 x) d x + (ln (x) - 4) d y = 0, x > 0