What is (\partial)/(\partial x)(4-x^2-2y^2) ?

The answer to (\partial)/(\partial x)(4-x^2-2y^2) is -2x

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(\partial)/(\partial x)(4-x^2-2y^2)

\frac{\partial}{\partial x} (4 - x^{2} - 2 y^{2})

- 2 x

Solution steps

\frac{\partial}{\partial x} (4 - x^{2} - 2 y^{2})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (4) - \frac{\partial}{\partial x} (x^{2}) - \frac{\partial}{\partial x} (2 y^{2})

\frac{\partial}{\partial x} (4) = 0

\frac{\partial}{\partial x} (x^{2}) = 2 x

\frac{\partial}{\partial x} (2 y^{2}) = 0

= 0 - 2 x - 0

Simplify

= - 2 x

\frac{d}{d x} (A x^{2} e^{3 x})

x \frac{d y}{d x} = 3 x e^{x} - y + 6 x^{2}

x \to 1 lim (x^{\frac{4}{1 - x}})

\int - x^{2} + 25 d x

y^{^{''}} + 3 y^{^{'}} - 40 y = 0

What is (\partial)/(\partial x)(4-x^2-2y^2) ?
The answer to (\partial)/(\partial x)(4-x^2-2y^2) is -2x