What is the integral of 2x^{-1/2} ?

The integral of 2x^{-1/2} is 4x^{1/2}+C

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integral of 2x^{-1/2}

\int 2 x^{- \frac{1}{2}} d x

4 x^{\frac{1}{2}} + C

Solution steps

\int 2 x^{- \frac{1}{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int x^{- \frac{1}{2}} d x

Apply the Power Rule

: 2 x^{\frac{1}{2}}

= 2 \cdot 2 x^{\frac{1}{2}}

Simplify

= 4 x^{\frac{1}{2}}

Add a constant to the solution

= 4 x^{\frac{1}{2}} + C

7 (4 x^{2} - 7 x + 2)^{- 6}

x \to \infty lim (x^{2} + 5)

x \to 2 - lim (\frac{x - 1}{x - 2})

x \to \frac{π}{2} lim (cos^{c o s (x)} (x))

t e^{2 t}