What is the tangent of y=sqrt(x),\at x= 1/4 ?

The tangent of y=sqrt(x),\at x= 1/4 is y=x+1/4

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tangent of y=sqrt(x),\at x= 1/4

tangent of

y = x, at x = \frac{1}{4}

y = x + \frac{1}{4}

Solution steps

Find the tangent point:

(\frac{1}{4}, \frac{1}{2})

Find the slope of

y = x : \frac{d y}{d x} = \frac{1}{2 x}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 1

Find the line with slope m=

1

and passing through

(\frac{1}{4}, \frac{1}{2}) : y = x + \frac{1}{4}

y = x + \frac{1}{4}

\int \frac{ln ^{5} ( x ^{2} )}{x} d x

\frac{d}{d x} (- 6 x^{2} + 6 x)

\int 2 (3 - e^{- t}) d t

\frac{2}{s ^{2} + 4 s + 3}

\frac{d}{d x} (- x^{2} sin (x^{2} y))

What is the tangent of y=sqrt(x),\at x= 1/4 ?
The tangent of y=sqrt(x),\at x= 1/4 is y=x+1/4