What is the integral from-4 to 0 of sqrt(y+4) ?

The integral from-4 to 0 of sqrt(y+4) is 16/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from-4 to 0 of sqrt(y+4)

\int_{- 4}^{0} y + 4 d y

\frac{16}{3}

Decimal

5.33333 \dots

Solution steps

\int_{- 4}^{0} y + 4 d y

Apply u-substitution

: \int_{0}^{4} u d u

= \int_{0}^{4} u d u

Apply the Power Rule

: [\frac{2}{3} u^{\frac{3}{2}}]_{0}^{4}

= [\frac{2}{3} u^{\frac{3}{2}}]_{0}^{4}

Compute the boundaries:

\frac{16}{3}

= \frac{16}{3}

\int \frac{10 x + 2}{( 3 x + 1 ) ( x - 1 )} d x

\int x^{2} + 8 d x

y

9 y^{^{''}} + 6 y^{^{'}} + y = 0

(2 y - x^{2} y) y^{^{'}} = x (y + 2)^{2}

What is the integral from-4 to 0 of sqrt(y+4) ?
The integral from-4 to 0 of sqrt(y+4) is 16/3