What is (\partial)/(\partial x)(ysin(xy)-2xy) ?

The answer to (\partial)/(\partial x)(ysin(xy)-2xy) is y^2cos(yx)-2y

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(\partial)/(\partial x)(ysin(xy)-2xy)

\frac{\partial}{\partial x} (y sin (x y) - 2 x y)

y^{2} cos (y x) - 2 y

Solution steps

\frac{\partial}{\partial x} (y sin (x y) - 2 x y)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (y sin (x y)) - \frac{\partial}{\partial x} (2 x y)

\frac{\partial}{\partial x} (y sin (x y)) = y^{2} cos (y x)

\frac{\partial}{\partial x} (2 x y) = 2 y

= y^{2} cos (y x) - 2 y

\frac{d}{d x} (x^{2} - 25 I n (x^{2}))

\int 2 y^{3} d y

\frac{1}{2} (2 (7.5) + 1)^{- \frac{1}{2}}

2 - x^{2}, 6 - 5 x

\frac{d}{d x} ((sin (7 x))^{l n (x)})

What is (\partial)/(\partial x)(ysin(xy)-2xy) ?
The answer to (\partial)/(\partial x)(ysin(xy)-2xy) is y^2cos(yx)-2y