What is the solution for y^'=(3x-2)(30x+29) ?

The solution for y^'=(3x-2)(30x+29) is y=30x^3+(27x^2)/2-58x+c_{1}

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y^'=(3x-2)(30x+29)

y^{^{'}} = (3 x - 2) (30 x + 29)

y = 30 x^{3} + \frac{27 x ^{2}}{2} - 58 x + c_{1}

Solution steps

y^{'} (x) = (3 x - 2) (30 x + 29)

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int (3 x - 2) (30 x + 29) d x

\int (3 x - 2) (30 x + 29) d x = 30 x^{3} + \frac{27 x ^{2}}{2} - 58 x + c_{1}

y = 30 x^{3} + \frac{27 x ^{2}}{2} - 58 x + c_{1}

\frac{d y}{d x}, 9 x^{2} + y^{2} = 1

x \to - \infty lim (x^{2})

\frac{d ^{2} y}{d x ^{2}} + 2 \frac{d y}{d x} = 12 x^{2}

\int \frac{( 2 x + 11 )}{x ^{2} + x - 6} d x

\int \frac{1}{x 49 + x ^{2}} d x

What is the solution for y^'=(3x-2)(30x+29) ?
The solution for y^'=(3x-2)(30x+29) is y=30x^3+(27x^2)/2-58x+c_{1}