What is the tangent of f(x)=x^4-2x^3-5x-3,\at x=1 ?

The tangent of f(x)=x^4-2x^3-5x-3,\at x=1 is y=-7x-2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of f(x)=x^4-2x^3-5x-3,\at x=1

tangent of

f (x) = x^{4} - 2 x^{3} - 5 x - 3, at x = 1

y = - 7 x - 2

Solution steps

Find the tangent point:

(1, - 9)

Find the slope of

f (x) = x^{4} - 2 x^{3} - 5 x - 3 : \frac{df ( x )}{d x} = 4 x^{3} - 6 x^{2} - 5

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 7

Find the line with slope m=

- 7

and passing through

(1, - 9) : y = - 7 x - 2

y = - 7 x - 2

\frac{1}{16 x ^{2}}, x, \frac{x}{10}

\int (3 x - 1) (x + 5) d x

f (x) = (3 + x^{5})^{3} - (2 + x^{3})^{4}

\frac{d}{d x} (arccos (\frac{4}{x}))

\int 7 x d x

What is the tangent of f(x)=x^4-2x^3-5x-3,\at x=1 ?
The tangent of f(x)=x^4-2x^3-5x-3,\at x=1 is y=-7x-2