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Popular >

y^{''}-2y^'+1=0

Solution

y^{^{''}} - 2 y^{^{'}} + 1 = 0

Solution

y = c_{1} e^{2 t} + c_{2} + \frac{t}{2}

Solution steps

y^{''} (t) - 2 y^{'} (t) + 1 = 0

Solve linear ODE:

y = c_{1} e^{2 t} + c_{2} + \frac{t}{2}

y = c_{1} e^{2 t} + c_{2} + \frac{t}{2}

Graph

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Frequently Asked Questions (FAQ)

What is the solution for y^{''}-2y^'+1=0 ?
The solution for y^{''}-2y^'+1=0 is y=c_{1}e^{2t}+c_{2}+t/2