What is the integral from 0 to 5 of t^3 ?

The integral from 0 to 5 of t^3 is 625/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 5 of t^3

\int_{0}^{5} t^{3} d t

\frac{625}{4}

Decimal

156.25

Solution steps

\int_{0}^{5} t^{3} d t

Apply the Power Rule

: [\frac{t ^{4}}{4}]_{0}^{5}

= [\frac{t ^{4}}{4}]_{0}^{5}

Compute the boundaries:

\frac{625}{4}

= \frac{625}{4}

14 (2 x + 5)^{6}

\int \frac{1}{1 - t - 2 t ^{2}} d t

\int_{0}^{10} \frac{1}{100 + x ^{2}} d x

\int e^{- i wt} d t

\frac{d}{d x} (- 3 x^{2} + 3)

What is the integral from 0 to 5 of t^3 ?
The integral from 0 to 5 of t^3 is 625/4