What is the solution for (dy)/(dx)=(x-3)/(2-y) ?

The solution for (dy)/(dx)=(x-3)/(2-y) is y=2-sqrt(-x^2+6x+4-c_{1)},y=sqrt(-x^2+6x+4-c_{1)}+2

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(dy)/(dx)=(x-3)/(2-y)

\frac{d y}{d x} = \frac{x - 3}{2 - y}

y = 2 - - x^{2} + 6 x + 4 - c_{1}, y = - x^{2} + 6 x + 4 - c_{1} + 2

Solution steps

\frac{d y}{d x} = \frac{x - 3}{2 - y}

Solve separable ODE:

y = 2 - - x^{2} + 6 x + 4 - c_{1}, y = - x^{2} + 6 x + 4 - c_{1} + 2

y = 2 - - x^{2} + 6 x + 4 - c_{1}, y = - x^{2} + 6 x + 4 - c_{1} + 2

f (x) = x \cdot ln (x)

y^{^{''}} + 16 y^{^{'}} + 65 y = 6 e^{- 8 t} cos (t)

(2 - 3 x)^{2}

\frac{d}{d x} (x^{2} - cos (x))

\frac{d y}{d x} = \frac{1 - y}{1 + e ^{x}}

What is the solution for (dy)/(dx)=(x-3)/(2-y) ?
The solution for (dy)/(dx)=(x-3)/(2-y) is y=2-sqrt(-x^2+6x+4-c_{1)},y=sqrt(-x^2+6x+4-c_{1)}+2