What is the derivative of sqrt(3+x) ?

The derivative of sqrt(3+x) is 1/(2sqrt(3+x))

What is the first derivative of sqrt(3+x) ?

The first derivative of sqrt(3+x) is 1/(2sqrt(3+x))

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derivative of

3 + x

\frac{1}{2 3 + x}

Solution steps

\frac{d}{d x} (3 + x)

Apply the chain rule:

\frac{1}{2 3 + x} \frac{d}{d x} (3 + x)

= \frac{1}{2 3 + x} \frac{d}{d x} (3 + x)

\frac{d}{d x} (3 + x) = 1

= \frac{1}{2 3 + x} \cdot 1

Simplify

= \frac{1}{2 3 + x}

x \to + 0 + lim (ln (2 x))

\int_{1}^{2} \frac{x}{2} d x

\int t t^{2} + 2 d t

\int \frac{y}{x} d x

n = 2 \sum \infty \frac{n}{( n - 1 ) !}

What is the derivative of sqrt(3+x) ?
The derivative of sqrt(3+x) is 1/(2sqrt(3+x))
What is the first derivative of sqrt(3+x) ?
The first derivative of sqrt(3+x) is 1/(2sqrt(3+x))