What is the derivative of sin(3x+cos(6x)) ?

The derivative of sin(3x+cos(6x)) is cos(3x)*3-sin(6x)*6

What is the first derivative of sin(3x+cos(6x)) ?

The first derivative of sin(3x+cos(6x)) is cos(3x)*3-sin(6x)*6

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\frac{d}{d x} (sin (3 x) + cos (6 x))

cos (3 x) \cdot 3 - sin (6 x) \cdot 6

Solution steps

\frac{d}{d x} (sin (3 x) + cos (6 x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (sin (3 x)) + \frac{d}{d x} (cos (6 x))

\frac{d}{d x} (sin (3 x)) = cos (3 x) \cdot 3

\frac{d}{d x} (cos (6 x)) = - sin (6 x) \cdot 6

= cos (3 x) \cdot 3 - sin (6 x) \cdot 6

\int e^{i wt} d t

\frac{d}{d x} (1 - (\frac{x + b + c}{( 3 a )}))

\int_{3}^{5} \frac{1}{x + 1} d x

\frac{d}{d x} (\frac{1}{2} e^{- \frac{x}{2}})

y^{^{'}} = x^{2} (1 - y)

What is the derivative of sin(3x+cos(6x)) ?
The derivative of sin(3x+cos(6x)) is cos(3x)*3-sin(6x)*6
What is the first derivative of sin(3x+cos(6x)) ?
The first derivative of sin(3x+cos(6x)) is cos(3x)*3-sin(6x)*6