What is the integral from 1 to infinity of x/(9+x^2) ?

The integral from 1 to infinity of x/(9+x^2) is diverges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 1 to infinity of x/(9+x^2)

\int_{1}^{\infty} \frac{x}{9 + x ^{2}} d x

diverges

Solution steps

\int_{1}^{\infty} \frac{x}{9 + x ^{2}} d x

Compute the indefinite integral:

\int \frac{x}{9 + x ^{2}} d x = \frac{1}{2} ln 9 + x^{2} + C

Compute the boundaries:

\int_{1}^{\infty} \frac{x}{9 + x ^{2}} d x =

diverges

= diverges

\int 1 + tan^{2} (x) d x

x \to 2 lim (\frac{g ( x )}{h ( x )})

\int sin^{6} (θ) d θ

x \to \infty lim (x^{2} - 3 x)

\frac{d}{d x} (50 sin (2000 x))

What is the integral from 1 to infinity of x/(9+x^2) ?
The integral from 1 to infinity of x/(9+x^2) is diverges