What is the integral of (ln(x^5))/x ?

The integral of (ln(x^5))/x is 5/2 ln^2(x)+C

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integral of (ln(x^5))/x

\int \frac{ln ( x ^{5} )}{x} d x

\frac{5}{2} ln^{2} (x) + C

Solution steps

\int \frac{ln ( x ^{5} )}{x} d x

Apply u-substitution

: \int \frac{ln ( u )}{5 u} d u

= \int \frac{ln ( u )}{5 u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{5} \cdot \int \frac{ln ( u )}{u} d u

Apply u-substitution

: \int v d v

= \frac{1}{5} \cdot \int v d v

Apply the Power Rule

: \frac{v ^{2}}{2}

= \frac{1}{5} \cdot \frac{v ^{2}}{2}

Substitute back

= \frac{1}{5} \cdot \frac{ln ^{2} ( x ^{5} )}{2}

Simplify

\frac{1}{5} \cdot \frac{ln ^{2} ( x ^{5} )}{2} : \frac{5}{2} ln^{2} (x)

= \frac{5}{2} ln^{2} (x)

Add a constant to the solution

= \frac{5}{2} ln^{2} (x) + C

\frac{2}{3} t^{2} + 5 e^{- 4 t}

x \to \infty lim (ln (3 x))

f (x) = \frac{16 x}{x ^{2} + 16}, at x = - 2

sin (x^{2})

\int \frac{( x ^{3} )}{x ^{2} + 4} d x

What is the integral of (ln(x^5))/x ?
The integral of (ln(x^5))/x is 5/2 ln^2(x)+C