What is laplacetransform 4(t-2) ?

The answer to laplacetransform 4(t-2) is 4/(s^2)-8/s

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laplacetransform 4(t-2)

laplace transform

4 (t - 2)

\frac{4}{s ^{2}} - \frac{8}{s}

Solution steps

L {4 (t - 2)}

Expand

4 (t - 2) : 4 t - 8

= L {4 t - 8}

Use the linearity property of Laplace Transform:

For functions

f (t), g (t)

and constants

a, b : L {a \cdot f (t) + b \cdot g (t)} = a \cdot L {f (t)} + b \cdot L {g (t)}

= 4 L {t} - L {8}

L {t} : \frac{1}{s ^{2}}

L {8} : \frac{8}{s}

= 4 \cdot \frac{1}{s ^{2}} - \frac{8}{s}

Refine

4 \frac{1}{s ^{2}} - \frac{8}{s} : \frac{4}{s ^{2}} - \frac{8}{s}

= \frac{4}{s ^{2}} - \frac{8}{s}

\int - 2 y^{3} d y

\frac{d}{d x} (\frac{1 - 6 ln ( x )}{x ^{7}})

\frac{d}{d x} ((sin (x))^{\frac{1}{x}})

x^{- 6}

n = 1 \sum \infty (- 1)^{n + 1} (\frac{1}{n} + \frac{1}{3 ^{n}})

What is laplacetransform 4(t-2) ?
The answer to laplacetransform 4(t-2) is 4/(s^2)-8/s