What is (\partial)/(\partial x)(-sin(y)+e^x) ?

The answer to (\partial)/(\partial x)(-sin(y)+e^x) is e^x

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(\partial)/(\partial x)(-sin(y)+e^x)

\frac{\partial}{\partial x} (- sin (y) + e^{x})

e^{x}

Solution steps

\frac{\partial}{\partial x} (- sin (y) + e^{x})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{\partial}{\partial x} (sin (y)) + \frac{\partial}{\partial x} (e^{x})

\frac{\partial}{\partial x} (sin (y)) = 0

\frac{\partial}{\partial x} (e^{x}) = e^{x}

= - 0 + e^{x}

Simplify

= e^{x}

\frac{5 x}{x ^{2} + 16}

\frac{d}{d x} (x \cdot tan (x))

\int \frac{5}{( 3 x - 1 ) ^{3}} d x

\int \frac{e ^{- 5 x} + 3 x e ^{x}}{2} d x

x \to + 3 lim (\frac{1}{( x - 3 )})

What is (\partial)/(\partial x)(-sin(y)+e^x) ?
The answer to (\partial)/(\partial x)(-sin(y)+e^x) is e^x