What is the integral of 1/(\sqrt[3]{x^5)} ?

The integral of 1/(\sqrt[3]{x^5)} is -3/(2x^{2/3)}+C

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integral of 1/(\sqrt[3]{x^5)}

- \frac{3}{2 x ^{\frac{2}{3}}} + C

Solution steps

assuming

x \geq 0

= \int \frac{1}{x ^{\frac{5}{3}}} d x

Apply the Power Rule

: - \frac{3}{2 x ^{\frac{2}{3}}}

= - \frac{3}{2 x ^{\frac{2}{3}}}

Add a constant to the solution

= - \frac{3}{2 x ^{\frac{2}{3}}} + C

\int e^{3 x + 8} d x

\frac{d}{d x} (\frac{cot ( x )}{1 + csc ( x )})

\frac{\partial}{\partial y} (x^{2} + 2 y + 2 z)

c^{^{'}}

\frac{d ^{4}}{d x ^{4}} (3 x^{4})

What is the integral of 1/(\sqrt[3]{x^5)} ?
The integral of 1/(\sqrt[3]{x^5)} is -3/(2x^{2/3)}+C