What is the derivative of-4sin(2x) ?

The derivative of-4sin(2x) is -8cos(2x)

What is the first derivative of-4sin(2x) ?

The first derivative of-4sin(2x) is -8cos(2x)

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derivative of

- 4 sin (2 x)

- 8 cos (2 x)

Solution steps

\frac{d}{d x} (- 4 sin (2 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 4 \frac{d}{d x} (sin (2 x))

Apply the chain rule:

cos (2 x) \frac{d}{d x} (2 x)

= cos (2 x) \frac{d}{d x} (2 x)

\frac{d}{d x} (2 x) = 2

= - 4 cos (2 x) \cdot 2

Simplify

= - 8 cos (2 x)

f (x) = arccos (e^{- x})

x \to \frac{1}{2} lim (8 x^{3} - 1)

x \to 2 lim (\frac{x ^{2} - 4}{x - 4})

\frac{1}{5 - 7 x}

\int 0^{2 π} sin (x) d x

What is the derivative of-4sin(2x) ?
The derivative of-4sin(2x) is -8cos(2x)
What is the first derivative of-4sin(2x) ?
The first derivative of-4sin(2x) is -8cos(2x)