What is the integral of (x^2sin(y)) ?

The integral of (x^2sin(y)) is -x^2cos(y)+C

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integral of (x^2sin(y))

\int (x^{2} sin (y)) d y

- x^{2} cos (y) + C

Solution steps

\int x^{2} sin (y) d y

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= x^{2} \cdot \int sin (y) d y

Use the common integral:

\int sin (y) d y = - cos (y)

= x^{2} (- cos (y))

Simplify

= - x^{2} cos (y)

Add a constant to the solution

= - x^{2} cos (y) + C

\frac{d}{d x} (\frac{1}{sec ( x )})

\int \frac{1}{x 2 x} d x

\frac{d y}{d x} = \frac{8 x 4 - y ^{2}}{4 - y ^{2}}

\int \frac{1}{( 1 + sin ( x ) )} d x

x^{2} - 4, - 2 x - 3, - 1, 0

What is the integral of (x^2sin(y)) ?
The integral of (x^2sin(y)) is -x^2cos(y)+C