What is the derivative of 1/((x+3)) ?

The derivative of 1/((x+3)) is -1/((x+3)^2)

What is the first derivative of 1/((x+3)) ?

The first derivative of 1/((x+3)) is -1/((x+3)^2)

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\frac{d}{d x} (\frac{1}{( x + 3 )})

- \frac{1}{( x + 3 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{1}{( x + 3 )})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{d}{d x} ((x + 3)^{- 1})

Apply the chain rule:

- \frac{1}{( x + 3 ) ^{2}} \frac{d}{d x} (x + 3)

= - \frac{1}{( x + 3 ) ^{2}} \frac{d}{d x} (x + 3)

\frac{d}{d x} (x + 3) = 1

= - \frac{1}{( x + 3 ) ^{2}} \cdot 1

Simplify

= - \frac{1}{( x + 3 ) ^{2}}

\int x^{3} (3 - x^{4})^{10} d x

\int x (6 x + 7)^{8} d x

\int x \cdot x^{10} d x

\frac{d y}{d x} y = x^{8 c o s (x)}

What is the derivative of 1/((x+3)) ?
The derivative of 1/((x+3)) is -1/((x+3)^2)
What is the first derivative of 1/((x+3)) ?
The first derivative of 1/((x+3)) is -1/((x+3)^2)