What is the integral of 1/(1+17x) ?

The integral of 1/(1+17x) is 1/17 ln|1+17x|+C

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integral of 1/(1+17x)

\int \frac{1}{1 + 17 x} d x

\frac{1}{17} ln ∣ 1 + 17 x ∣ + C

Solution steps

\int \frac{1}{1 + 17 x} d x

Apply u-substitution

: \int \frac{1}{17 u} d u

= \int \frac{1}{17 u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{17} \cdot \int \frac{1}{u} d u

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= \frac{1}{17} ln ∣ u ∣

Substitute back

u = 1 + 17 x

= \frac{1}{17} ln ∣ 1 + 17 x ∣

Add a constant to the solution

= \frac{1}{17} ln ∣ 1 + 17 x ∣ + C

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What is the integral of 1/(1+17x) ?
The integral of 1/(1+17x) is 1/17 ln|1+17x|+C