What is the limit as x approaches 6 of \sqrt[3]{x-6} ?

The limit as x approaches 6 of \sqrt[3]{x-6} is 0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches 6 of \sqrt[3]{x-6}

0

Solution steps

Plug in the value

x = 6

Simplify

= 0

x = y^{2} - 8, x = 2 y

\frac{d}{d x} (\frac{x - 3}{x} + ln (\frac{x}{3}))

x \to \infty lim (3 ln (x))

k

\int_{2}^{2} \frac{u}{u ^{2} - 1} d u

What is the limit as x approaches 6 of \sqrt[3]{x-6} ?
The limit as x approaches 6 of \sqrt[3]{x-6} is 0