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Popular >

area y=x^2+2x+1,y=2x+5

Solution

area

y = x^{2} + 2 x + 1, y = 2 x + 5

Solution

\frac{32}{3}

+1

Decimal Notation

10.66666 \dots

Solution steps

Apply the area formula:

\int_{- 2}^{2} x^{2} + 2 x + 1 - (2 x + 5) d x

Solve

\int_{- 2}^{2} x^{2} + 2 x + 1 - (2 x + 5) d x : \frac{32}{3}

The area is:

= \frac{32}{3}

Popular Examples

(\partial)/(\partial x)(-6xy)

\frac{\partial}{\partial x} (- 6 x y)

derivative of 1/5 x^5+1/(12x^3)

\frac{d}{d x} (\frac{1}{5} x^{5} + \frac{1}{12 x ^{3}})

x^2y^'-2xy=sin(4x)x^4

x^{2} y^{^{'}} - 2 x y = sin (4 x) x^{4}

maclaurin arctan(3x)maclaurin

arctan (3 x)

d/(dt)(sin^2(t))

\frac{d}{d t} (sin^{2} (t))

Frequently Asked Questions (FAQ)

What is area y=x^2+2x+1,y=2x+5 ?
The answer to area y=x^2+2x+1,y=2x+5 is 32/3