What is the solution for (2x-4)(dy)/(dx)-y^2=0 ?

The solution for (2x-4)(dy)/(dx)-y^2=0 is y=-2/(ln(2(-2+x))+c_{1)}

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(2x-4)(dy)/(dx)-y^2=0

(2 x - 4) \frac{d y}{d x} - y^{2} = 0

y = - \frac{2}{ln ( 2 ( - 2 + x ) ) + c _{1}}

Solution steps

(2 x - 4) \frac{d y}{d x} - y^{2} = 0

Solve separable ODE:

y = - \frac{2}{ln ( 2 ( - 2 + x ) ) + c _{1}}

y = - \frac{2}{ln ( 2 ( - 2 + x ) ) + c _{1}}

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What is the solution for (2x-4)(dy)/(dx)-y^2=0 ?
The solution for (2x-4)(dy)/(dx)-y^2=0 is y=-2/(ln(2(-2+x))+c_{1)}