What is the tangent of f(x)=(4x)/(x^2+1),(0,0) ?

The tangent of f(x)=(4x)/(x^2+1),(0,0) is y=4x

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tangent of f(x)=(4x)/(x^2+1),(0,0)

tangent of

f (x) = \frac{4 x}{x ^{2} + 1}, (0, 0)

y = 4 x

Solution steps

Find the slope of

f (x) = \frac{4 x}{x ^{2} + 1} : \frac{df ( x )}{d x} = \frac{4 ( - x ^{2} + 1 )}{( x ^{2} + 1 ) ^{2}}

Compute the slope of

f (x) = \frac{4 x}{x ^{2} + 1}

(0, 0) : m = 4

Find the line with slope m=

4

and passing through

(0, 0) : y = 4 x

y = 4 x

\int_{1}^{3} \frac{1}{( x - 1 ) ^{\frac{3}{2}}} d x

\int \frac{1}{2 sin ( x ) + cos ( x )} d x

y^{^{'}} = 2 y + x e^{x}

x \to + 0 lim (\frac{ln ( x )}{x})

y = (1 + 4 x)^{8}, (0, 1)

What is the tangent of f(x)=(4x)/(x^2+1),(0,0) ?
The tangent of f(x)=(4x)/(x^2+1),(0,0) is y=4x