What is the solution for (dy)/(dx)+4tan(4x)(y)=3cos(4x) ?

The solution for (dy)/(dx)+4tan(4x)(y)=3cos(4x) is y=(3x)/(sec(4x))+(c_{1})/(sec(4x))

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(dy)/(dx)+4tan(4x)(y)=3cos(4x)

\frac{d y}{d x} + 4 tan (4 x) (y) = 3 cos (4 x)

y = \frac{3 x}{sec ( 4 x )} + \frac{c _{1}}{sec ( 4 x )}

Solution steps

\frac{d y}{d x} + 4 tan (4 x) (y) = 3 cos (4 x)

Solve linear ODE:

y = \frac{3 x}{sec ( 4 x )} + \frac{c _{1}}{sec ( 4 x )}

y = \frac{3 x}{sec ( 4 x )} + \frac{c _{1}}{sec ( 4 x )}

\int_{- 2}^{3} (x^{2} + 3 x - 13) d x

x \to 0 lim (arctan (ln (x)))

(cos (x) sin (x))^{^{'}}

\frac{\partial}{\partial x} (3 x e^{- x y})

e^{- 2 s} \frac{1}{10 s + 2}

What is the solution for (dy)/(dx)+4tan(4x)(y)=3cos(4x) ?
The solution for (dy)/(dx)+4tan(4x)(y)=3cos(4x) is y=(3x)/(sec(4x))+(c_{1})/(sec(4x))