What is (\partial)/(\partial x)(r(θ,x)cos(θ)) ?

The answer to (\partial)/(\partial x)(r(θ,x)cos(θ)) is rcos(θ)(θ,1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)(r(θ,x)cos(θ))

\frac{\partial}{\partial x} (r (θ, x) cos (θ))

r cos (θ) (θ, 1)

Solution steps

\frac{\partial}{\partial x} (r (θ, x) cos (θ))

Treat

r, θ

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= r cos (θ) \frac{\partial}{\partial x} (θ, x)

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= r cos (θ) (θ, \frac{\partial}{\partial x} (x))

Apply the common derivative:

\frac{\partial}{\partial x} (x) = 1

= r cos (θ) (θ, 1)

x \to 3 - lim (\frac{3}{x ^{2} - 9})

\int_{1}^{3} \frac{x ^{2} + 5}{4 x - x ^{2}} d x

\frac{d}{d x} ((\frac{1}{1 - x})^{2})

\frac{d}{d x} (15 x^{4})

\frac{2}{x} - 1

What is (\partial)/(\partial x)(r(θ,x)cos(θ)) ?
The answer to (\partial)/(\partial x)(r(θ,x)cos(θ)) is rcos(θ)(θ,1)